I have a series of file names in a text file that I generated by running
Code:
bash-4.1# ls -alt *.txz | awk '{print $8}'
and then copy pasting the output. All of these file names have the version number
Quote:
-4.4.1-x86_64-1alien.txz
I just want a method to remove that version number from all the filenames so that I can then add all the packages without version numbers to a blacklist file.
I've tried kwrite and mousepad and both have a search feature and a replace feature but I haven't been able to just have the text removed successfully.
What i want to do is pretty simple.I want to uncomment every line that begins with "deb" (except for deb cdrom) in /etc/apt/sources.list.I know how to do this through system > administration > software sources.I know I can gksu gedit /etc/apt/sources.list.I'd rather not do it that way.I'd rather have a script do it. It's less work, less typing, less clicking, and would work the same on every ubuntu version.
I need to find a string in a file ... then delete the line it is on, as well as the next 6 lines. Or, delete the line the string is on and all subsequent lines until the search finds the character "["
example:
filename = test.txt
contents: [foo] test>test test>test test>test
[Code]....
so, in this example. I'd like to search the file for string 'foo' and delete all lines from that line until [bar] (not deleting the line with [bar])
[Syenite] RegionUUID = 8fc56fdd-0afd-4074-9432-0ae8f42b799f Location = 9992,10007 InternalAddress = 0.0.0.0 InternalPort = 9000 AllowAlternatePorts = False ExternalHostName = 71.171.21.9 What I need to do is find out what the IP address is after "ExternalHostName ="
After that I will need to compare that IP to whatismyip and if it's different then replace it but that is easy to do with sed. I just can't figure this simple hurdle out.
write such script (bash script). I have some text file with name filename.txt I must check if this file contains string "test-string-first", I must cut from this file string which follows string "keyword-string:" and till first white-space and save it to some variable.
For example. File: PHP Code: PHP Code: Start 15022011 Eng 12-3-42 SN1232324422 11 test-string-first SN322211 securities HH keyword-string:123456321-net mark (11-22)
I am a member of a group which has written a program whose source code is being held in a specific directory (~cs252/Assignments/basicAsst/project) and we want to go through and change the parameters for the function "sequentialInsert." My job is to find all occurances of the function call to "sequentialInsert" and to also list the files from where the code came from. Also, I have to be in the commandsAsst directory when I do this. I have tried grep and find combined together, and I am at a lost.
We had seen some time ago, various tricks to remove the character MS-DOS text files on Linux. Here is a new trick to do this directly from the vim editor. to convert a file opened with vim in UNIX format, simply use the following command code...
Through various Windows reinstalls and switches within Linux distros, I have a massive amount of duplication within my music archive (on the order of 7+ dupes of each file). Now, I found a lovely program called "fdupes" and was able to build a list of all the duplicate files, and I'm trying to use "xargs" to remove then. However, when I try and run the command "xargs -0 --arg-file="dupes.txt" rm" or "xargs -0 rm < "dupes.txt"" it give me the following error: "xargs: argument line too long".
how perhaps a different way of accomplishing the same thing?
Is there a way to specify to find that I only want text files (and not binary files)? Grep has an option to exclude binary files, so I thought find probably has a similar feature, but I've been unable to find it.
I have a line in a text file that has 40 random characters within a tag and i want to change the characters to a new set of 40 random characters (alphanumeric a-z 0-9 etc)
The line in the text file looks like this:
Quote:
How would i go about doing that?
Also second question same as the above but how would i remove them instead of replacing them?
After hours (literally) of searching the web and reading man pages, I think I've come up with the following:Code:find . -exec grep 'path/to/file' -print | xargs -0 -I new_path mv {this is where I get confused}So my code above is incomplete, obviously. In order to finish replacing the string, I need to mv the new file into the old file's spot. How do I do this, by incorporating it into my line of code?
If I have a word in a text file and I need to replace it by another word (for example, i need to replace abc by fff) so what is the command I can type it?
The problem I have is that I need to replace a more complex string, like this: Old string: /mnt/stor6-wc2-dfw1/627896/982574/ New string: /mnt/stor8-wc2-dfw1/369587/302589/ There I don't know how to do it... since the / is what separates the old from the new strings, and the strings that I want to replace have / in it. Also, I would like to know how to specify under what folder replace the files, for example, I want that it search/replaces all files under /var/www/mysite/htdocs folder.
I am looking for Windows Search equivalent looking for file name patterns (not file contents but file names)....
I am aware of "globbing" and wildcard recursive search functionality in ls but I am still not capable of finding files under directories.
for example: I want to find all files starting with a string lsnr* under root directory / and any sub-directories.....
ie I want to look for files like lsnr*.* anywhere under / and any sub-directories under / such as /dir1/dir2/dir4 and dir1/other/dir/someotherdir/sub-dir etc.
so if I have /dir1/lsnrcontrol and also have /dir1/dir/2/dir3/lsnr-tinit.dat then I want to list the files names etc.
I want to use the shell to find .zip files in my music directory and all sub directories and then delete only these files. The following will find the files I want to delete
Code:find /home/me/Music/ -name *.zip -lsWhat is the next step to delete *only* these files.Would it be a good idea to move them to another directory before doing the final rm - how would I do this
I want find a bunch of log files and delete ones that are older than say 5 days. Ideally I would then like to add this my crontab to run once a day.
The log files are in /var/log and are owned by root. They have a standard naming convention which is [date]RootCronRsync-backupHOME.log An example file is 20100621RootCronRsync-backupHOME.log Trying to put together a bash script to do this I think I need something like
Code: find /var/log/ -name *RootCronRsync-backupHOME.log -mtime +5 -exec rm {} ; However if I try this without the -exec rm (ie to see if I can find the right files first) I get the following error find: paths must precede expression: 20090405RootCronRsync-backupHOME.log Usage: find [-H] [-L] [-P] [-Olevel] [-D help|tree|search|stat|rates|opt|exec] [path...] [expression]
I have a directory containing a ton of photos, some of which are duplicates but just with different names. Is there any way in linux to find all the duplicates and remove all of them except the most recent version? I know on Windows there are utilities that will do this through a GUI, but I'm using Linux through the CLI only.
Need to make sure a security line is added in to every webpage on a site, trying to find out how to list only the filenames of the pages that are missing the text. awk or grep? o what I want is to list all files NOT containing the word 'securemasthead'
I have a many directories each with about 20 html files inside. All the files have .html ext. What I'm hoping is possible is from command line to find some text in each one and replace it with some other text.
Basically what I want to replace is;
/awstats/ with awstats/
I can do this easily with dreamweaver or some other application but because I have 960 pages total to do I'm hoping to do it this way.
I have to delete a certain line of text from the a textfile via ubuntu's shell scripting.I have done research, and it seems that most people advocate the usage of sed /d option. sed makes does not edit the text file. Hence, most options I discovered involved the use of a temporary variable/textfile and then overwriting the old file with the temporary new file. Is there anyway whereby I can bypass the use of temporary storage containers? I hope there is any magical combination of commands to edit the file directly.
I'm pretty sure this is doable from the command line, but my CLI skills have degraded a lot since my pre-Y2K admin days. The goal is to search all the files in the directory for a very long string of text and replace it with another string of text. The text being searched for is my Google Adsense code (which will be stripped from my website) and it will be replaced with a placeholder so I can easily tack something else in there in the future.
Seeing how I have that long snip of code on about 100 pages, automating the process would make life easier. If I was searching for a single word, I can see ways to do this. If I paste the code I'm searching for into a text file, is there a way to: find (contents of oldstring.txt) and replace with (contents of newstring.txt)?
15 this is a sentence containing various words and spaces 34 this is a another sentence containing various words and spaces
cat file2.txt
2 this is sentence1file2 6 this is sentence2file2 54 this is sentence3file2
I would like to join these 2 files. The result should look as follows :
cat joinedfile.txt
2 this is sentence1file2 6 this is sentence2file2 15 this is a sentence containing various words and spaces 34 this is a another sentence containing various words and spaces 54 this is sentence3file2
==> so the joined file must be sorted on the first number. Any ideas how this can be achieved ?
I have the following string 1524)), I want to get rid of the parentheses. I have tried SED and AWK without success. The last I tried was: echo "1526))" | sed 's/)).*$//'
These must a be a question you received a lot, but I couldn't find a similar thread! It's a simple question. I need to delete a specific string from a file. For example the specific numbers "3456" from a file. I've tried with the tr comand, using Code: tr -d '3456' file, but it also deleted whichever ocurrence of 3,4,5,6 from my file. Should I use a regular expression?
