I have a question about sed programming, actually a one-liner for which I cannot find a solution, right now. I need to delete a line matching a specific pattern only if it is the last line. In practice, I would put together the following:
Code:
#
# This deletes the last line of a file
[code]...
I have this complex log file filled with entries like
test1-G1/0/0-100-QOS-7001923-ROUTING (ClassMap)
Action: Resolved New
sysName: test1.local
[code]...
if the given pattern exists in the file with the very next line starting and endingwith the same pattern , delete the line that starts and ends with the given pattern.So upon running on this file
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scripts
[code]....
Quote:Originally Posted by topcatI would like to know how i can write a shell script to delete a line if a particular pattern exists?E.g. I have a text file with multiple lines. Say 1000s. in the following pattern.
username@email.com:149.0.3.4:1
username1@email.com:149.0.3.4:1
username1@email.net:149.0.3.4:1
username1@email.edu:149.0.3.4:1
If the patternusername@email.com exists then the line "username@email.com:149.0.3.4:1 should be deleted from the file.I have a very similar question but I need to delete one line in a file which matches one very precise instance of a string only. Let's assume I have a file composed of thousands of lines and let's call the file chap-secrets. Let's take the following sample entries:
Code:
#USERNAME SERVER PASSWORD IP
pp pptpd blahblah *
[code]....
I've written a script to parse a file and print each line that ends with matching pattern, if the next line is blank. The pattern lines are the result of md5sum $i|sed 's/path///g' so that only md5 and filename appear. Here's what I'm using.
Quote:
for fline in `sed -n '/.*.ext$/p' file1`
do
if [ "`sed -n -e '/'"$fline"'/ {n; p;}' file1`" == "" ]
then
echo ""$fline" has no info" >>file2
fi
done
[Code]....
How can I use grep -Ev "pattern" not only to delete the matching "pattern" but to edit and save the file permanently as well
View 2 Replies View RelatedI am trying to create a shell script, on taking a input file as parameter, which need to do 3 things
1) create a copy of existing file.
2) add a new line to the copied file.
3) strip off all the absolute paths inside the copied file
The first 2 points are straight forward. but i am finding it difficult to acheive the 3rd point. myself not very good with awk and sed. but gave it a shot in vain. For example, the input script consists of below,
PROGRAM=`/usr/bin/basename $0`
HOST=`/usr/bin/uname -n`
echo Start $PROGRAM `/usr/bin/date` |
/usr/bin/tee -a $LOG
The output of the script should look like,
PROGRAM=`basename $0`
HOST=`uname -n`
echo Start $PROGRAM `date` |
tee -a $LOG
I've got files in a directory as follows:
1.png
1_thumb.png
1-1.png
1-1_thumb.png
[code]....
I want to list all the files that don't have a copy with the same filename with -1 somewhere in it. So, in the example above, the results would be 3.png.
NB: the file and its copy with "-1" in it will be the same filesize, if that helps.
I need to add some text using sed before and after the matching pattern. Does any one have any clue?e.g.cat /my/file | sed -e "s/first pattern/New Pattern/g" . /my/file.bakNow I need a result like New Pattern
View 7 Replies View Relatedi tried searching on google but found it difficult to say exactly what I was looking for.Task - Capitalise x number of letters at the start of words.eg. Original line - one.two.three.fourRevised line - One.Two.three.four (here only requiring 2 changes)Test data:
Code:
wire.in.the.blood.s04e01.ws.pdtv.xvid-river.avi
wire.in.the.blood.s04e02.ws.pdtv.xvid-river.avi
[code]...
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI am interested in the following problem: given a string (pattern) find a regexp which match this pattern.
I will need this for a developing of an idea 'pattern based filtration'.
I have found many information about how to delete/grab a line in a text file including delete line with match a pattern but I did not find info about how to delete a line which match a pattern of a particular column only.
for example mydata.txt:
id type x y z
1 6 0.474611 0.227223 0.583947
[code]....
I am trying to edit a print file.
For every occurence of the ^L form feed character I need to remove 5 blank lines after it but still keep the ^L.
I am a rare user of sed and am ok with the basics but am struggling with this.
I have such a file(test.txt):
abc 123 456
abc 256 145
axd 125 225
[code]...
I have a file with a number of strings like the ones below
string1#m1asdfe23easdf23wefas
string2#mfaaeb2vr1rhserh
anotherstring#ji89ensrsegr
anotherone#m1ynmdt324nsdt
I'm trying to delete everything after #** so that
string1#maasdfeaveasdfawefas
string2#mfaaebvrserhserh
becomes
string1#ma
string2#mf
tried sed 's/#..*//g' but as you all will know it returns string1, string2 etc.
I have a file like so:
Code:
one
two
three
four
I would like to insert prior to the word "three" all items from this second file with the following contents:
Code:
four
three
two
one
Now my issue is, and I have been using both sed and awk currently, that after the second line of the new file is read there will of course now be 2 copies of the word "three" but I would like to only insert the final 2 words, ie "two" and "one" prior to only the first occurrence of the word "three" so final file will look like:
Code:
one
two
four
[code]....
So here there is now only one of each word from the second file joined to make the new file. For simple code I have tried something like the following:
Code:
while read line
do
awk -v n=$line '!f && /three/{print n;f++}1' file1 > tmp_file
mv tmp_file file1
done < file2
Now this works but seems very clumsy to me. There is obviously a better sed and / or awk out there.
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I have a requirement to list files using find command My folder contains below list of files with out extention.I have a requirement to exclude only ABC.123.* type files and list others. Even though files having MNO contains this pattern i should not exclude. Even if file ends with .txt or .doc it should not be excluded. That is ABC.123.1234.txt should not be excluded.But I am not getting what is required. Can any one please let me know if I am doing wrong any where. As per my requirement I cannot use grep, -regex, or -regex attributes to find command.
View 7 Replies View RelatedIf I wanted to copy all *.so files from src to dst I'd do:
cp src/*.so dst
However, I want to copy all *.so files from src and it's subdirs into dst.
Are there some good tutorials or reference materials on how do pattern matching and text manipulation in Linux?I have a few simple tasks I'd like taken care of...like formatting numbers in file names, stripping some text from directory names, etc
View 2 Replies View RelatedWas wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
I have two table files with x (1st column) ,y (2nd column) coordinates and intensity (3rd column). I need to match these two tables and divide the intensities at the consecutive coordinates on the 3rd column. The problem is the size of the tables are not same and I want to ignore the lines if they are not in one of the other file.
Here is Table 1:
Code:
-7.500-30.00013.006
-7.500-22.50037.952
-7.500-15.00060.962
-7.500-7.50040.922
-7.5000.00014.348
code....
I have to enhance the behaviour of a backup script written in perl. I don't need to change it, what I need to do is to create a bash script that does some checks like file name and file size, execute the backup script then check if the backup files match the original files.Here's how I try to do it:
- read the files from the original files folder
- store them in an array
- search in the array the files that have a specific file extension
- store the file names that match the search pattern (I know the backup script skips some files so I can hardcode the search pattern)
- run the backup script
- read the files from the backup folder
- store them in an array
- compare the original files name and size stored in an array with those from the backup folder
- send a report email
I need to grep for a particular string and if found need to display the line containing that string, the line above that and also the first line of that paragraph.
Can this be done via sed.
Eg, My Paragraphs
OA connectA
Enclosure:
Interconnect Module #6 Status:
Here, if I grep for Critical, it should display the following
Similarly if I grep for Degraded, it should display
I want to delete lines which contain the word "Fehler" but for some reason my programm isn't working:
Code: BEGIN { FS="|"
OFS="|"
SUBSEP="|"
[code]...
I would like to delete a single line from a file that contains many lines passing through the same values as the two parameters. Again, I would like to delete a single line and not all those that contain parameters. How can I make bash?
View 14 Replies View RelatedDelete this with maximum prejudice, mods.
View 1 Replies View Relatedi have a file containing contents as
1 2 3
2 2 3
11 2 3
now i want to delete the line which first column content is 1. so, if i pass the parametere 1 to function delete_row. is should remove the first row as
2 2 3
11 2 3
and then write the contents in file.
How can I remove all .swp files in all of my subdirectories under Linux?
View 4 Replies View Related