Programming :: Case Statement Passing Multiple Arguments?

Aug 7, 2010

I've started dabbling with the case statement in order to pass some option's arguments into variables. I do not think I am doing this right.

Code:

usage() {
echo "Usage: $0 [-z|--snooze] [-c|--channel] [-p|--playlist]
[-m|--message] [-v|--mpcvolume]"

[code]....

As you can see, I want to pass arguments depending on the option(s) chosen by the user; ie. --snooze, or --channel. By default, if no options are chosen, I'll display a usage message; though in the future I'll provide some sane defaults. I'd like to create a case statement to handle passing arguments to any number of options; something like:

Code:

wakethehellup.sh --snooze 20 --message 'wake up!'

and for the other arguments, it would have a default set. The case statement I provided fails with a syntax error "syntax error near unexpected token `$2'" near the '--snooze' in the statement, so I take it you can't pass a parameter in this way; but I'm confused as to how I'm supposed to pass different parameters to different options without the options being confused as parameters.

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I've written a simple perl code to learn switches in perl.My code is pasted below,

#!/usr/bin/perl
$opt = 1;
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This is my script:

Code:

while [ -n "$1" ]
do
lines=`cat $1 | wc -l`
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Code:
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case $1 in

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Code:

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Code:

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I want to write a little time-saving alias for my .cshrc file that will move files and then cd to the directory I've moved them to. What I can't quite figure out is the syntax to say 'move all the arguments except the last one.' Here is what I have:

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This actually seems to work, but it also gives me an irritating error:

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Similarly, I tried:

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I need to write a wrapper function around the mvprintw function, like so:

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How should I write the args for smvprintw so that I can pass all the data correctly to mvprintw, and also do my checks on the first two args (for example, to modify them)? I'm confused by the prototype of mvprintw: This is mvprintw as listed in the man pages:

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Quote:

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[code]....

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Code:
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I am facing problem with the following script. Could you please look into this.echo 'Enter Staging number' case $STGNUM in

1)
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I need "fill" passed along as $2 intact

Here is the bash line:

As you can see after the -f it has to be in single quotes and $FILL will complete the single quote

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I am pasting the source code documentation below:

SCANMATCHER:

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Here's my need:
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I have written a script to automatically retrieve imdb artwork for a given filename. Here is the script:

Code:

You can ignore all the commented "echo" commands that was just me testing. Anyway, the script work fine, however I am trying to use incrontab to monitor a folder, when a new (video) file is moved into the folder, it should execute the script and retrieve the artwork. My problem is, when incrontab passes the $# argument to my script, the script wont work because the spaces aren't escaped.

Here is some more detail:

Incrontab

Code:

Code:

The problem is, the script GetArtwork, doesn't see "Bangcock Dangerous" it just sees "Bangcock"

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[Code]...

# If the user enters their own userid they will get a comment saying 'correct' $LOGNAME) echo "Correct";;

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The code:

Quote:

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Code:
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[code]...

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[Code]....

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