Programming :: Checking For Alphabets ?

Jan 25, 2010

Code:

I am trying to do a search to check if the input is using alphabets and nothing else.

I tried using [[:digit:]] and [[:alpha:]] but none seems to work

When i use digit, it read 22.k as alphabet and not as a wrong syntax.

For alpha , it does not allow me to input data which has spaces such as " hello world".

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Programming :: Data Validation - Input Contains Digits And Certain Alphabets

Apr 8, 2010

I am having a huge problem checking the data I input to make sure it is correct. What I am trying to achieve is when I input a value, it will check if the input is all digits and if it is not, check to see if it contains certain alphabets. Thus for example, if I were to input in data such as "11A" , the program will then inform me "There is an important alphabet in the program." This would be my expected output. Here is the program I have wrote...

Code:
int test(string r ){ const int arraySize = 10;
char array2[arraySize2] ={'A','B','E','F','G','H','J','K','N','O','P','Q','R','S','T','U','W','Y','Z'};
for(int cntr = 0; cntr <r.length(); cntr++)
if(!isdigit(r[cntr])){ for(int new1 =0; new1<arraySize2;new1++)
for(int cntr1 = 0; cntr1 <r.length(); cntr1++)
if(array2[new1] == r[cntr1]){ return 2; //will return2 when it finds the same
// char in the array and the string r. } else{ return 3;
//will return 3 when there is a char
//in the string which isnt in the array
} } else { return 1; // will return 1 when string is all digit.
} int main() { string r = "11D"; test(r);
if(test(r) == 1) { cout << "ALL ARE DIGITS" << endl;
} if (test(r)== 2) {
cout << "There is an important alphabet in the program." << endl;
} if (test(r)== 3) { // testRoman(r);
cout << "There is an Alphabet in the String which is not in the Array" << endl;
} }

So, the problem I am facing is when I input in data such as 11 or A , the prog will come out the right input. But if I were to put in data such as "11A" , the output coming out will be "ALL ARE DIGITS". The problem which causes this seems to be in the return statement , as once as it finds the first char which is a digit, it will then return 1 and not continue checking the rest of the string. Is there a way I can stop or continue a loop if it has met the condition I stated? What I can do or any other way available for me to check my input?

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Code:
#!/bin/bash
#####################################################
# check_rbl
#####################################################
# 17-12-2010 by JP van Melis
#

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I have installed at least 10 different Urdu fonts but still no help, then I tried adding:

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Code:
echo "read this"
read this

[code]....

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[code]....

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Code:
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Code:
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#include<string>

[code]....

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Code:
Database.txt
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Code:
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Code:
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which means
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Code:

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Code:

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Code:
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