Is there a non-root shell command that can tell me if a user's account is disabled or not? note that there is a fine distinction between LOCKING and DISABLED:
LOCKING is where you prepend ! or * or !! to the password field of the /etc/passwd file. On Linux systems that shadow the passwords, this marker flag may be placed in /etc/shadow instead of /etc/passwd. Password locking can be done (at a shell prompt) via password -l username (as root) to lock the account of username, and the use of the option -u will unlock it.
DISABLING an account is done by setting the expiration time of the user account to some point in the past. This can be done with chage -E 0 username, which sets the expiration date to 0 days after the Unix epoch. Setting it to -1 will disable the use of the expiration date.
The effect of locking to to prevent the login process from using a supplied password to hash correctly against the saved hash (by virtue of the fact that the pre-pended marker character(s) are not valid output character(s) for the hash, thus no possible input can ever be used to generate a hash that would match it). The effect of disabling is to prevent any process from using an account because the expiration date of the account has already passed.For my situation, the use of locking is not sufficient because a user might still be able to login, e.g. using ssh authentication tokens, and processes under that user can still spawn other processes. Thus, we have accounts that are enabled or disabled, not just locked. We already know how to disable and enable the account - it requires root access and the use of chage, as shown above.To repeat my question: is there a shell command which can be run without root privileges which can output the status of this account expiration info for a given user? this is intended for use on a Red Hat Enterprise 5.4 system.The output is being returned to a java process which can then parse the output as needed, or make use of the return code.
I want to execute a bash script that switches user and then executes a series of commands. None of this users have root privileges. I guess I have to edit the sudoers file to give user1 (the user executing the script) privileges to be able to log as user2 with no password prompt. I've been looking for this example but I haven't found any.
I am trying to log into a server with a particular account. Let's say I don't know the password for that account. Can I do this using ssh? I am wondering if it is possible to do it in one command, instead of logging in as root and running su.
Can't seem to use tcsh as my login shell under CentOS 5 as I used to (if I specify /bin/tcsh as my start-up shell, the windowing system doesn't come up), so am logging in under bash then switching to tcsh on top of that, but it won't allow display access from tcsh for my programs. Gives the "cannot connect to display" error that usually xhost + is the solution for, but xhost doesn't help in this case (won't even run under tcsh, says unable to open display "0.0"). $DISPLAY is set in .cshrc. Must be something simple, but can't seem to find a direction to head?
I deleted the root line in passwd and shadow and then tried to copy the backup and was able to put it all back to normal from rescue mode. However when i get to my login screen i can not login as root anymore or even after logged in as another user i can not su - or su root, it tells me that root user does not exist......
I have set up my crontab and whilst Im logged in and it works (It runs my shell script), however when Im not logged in, the script does not run. Initially I set the time/date to 0 0 * * * (Midnight every day), as this did not work, I tested it with to 0 * * * * (every hour) whilst logged in and the script starts.
I use crontab -e to set it up under the root account..Im sure you dont have to be logged in for it to run?, but maybe im missing a step or just overdosing on Linux and need a holiday:-)
I want to add a new user. For that purposeI switch to su and give root passwd. There I gave a command " useradd ". [smith@localhost smith]#adduser when i press enter key by typing adduser command it say me "Command not found" .Then i log off from my own account and login again from root account. The command "useradd" is then accepted.is there any way that without logging off from normal user account I may enter my roor accout and work as a root account instead to log off from normal user account.
In the ubuntu series I find my hard disk description as this: /dev/sda. As we know in slackware (10.1) for partitioning we either use 'fdisk' or 'cfdisk' when I use fdisk, like mentioned: fdisk /dev/sda. It says disk cannot be found.... or something like that. I think I know why?
You see my hard disk has the D: E: F: as extended partitions comprising logical drives and only my C: drive is pure primary. Does this have any connection with my problem? As from my explanation you can find that I'm a total wreck with computers.. but I'm very thrilled to learn linux. The reason why I need slax is that I require a traditional root account.
I've started to get emails that would typically come from [URL] as [URL]. These emails come from services that send out emails (backup programs) directly, or from cronjobs. I've logged in as the non-root account and either sudo su - or su - to root and the restart the service at one point or another. If I login directly as root and bounce the service or cron the emails come across as from root. I don't see anything in my environment variables after I su to indicate what would cause this. I'm not sure where else to look? A pam setting? This seems to have happened between Fedora 10 and 14 (did a bunch of overdue upgrades recently) I've only got Fedora so I don't have anything to compare to. In Fedora 10 I did not have this problem.
I used c-shell previously in unix. One of the useful command I used frequently is foreach.> foreach a (`cat list`)>> echo $a need to use bash shell now instead, and realized that I can't use foreach anymore. The command is not found. Does anyone knows if there is similar command / function in bash shell?
This causes Tomcat to be run as myuser, which is expected. However after issuing the reboot command the system starts up and root is now the owner of this process. How can I force the process to be started off as myuser on reboot?
On a Fedora Core box, I have a normal non-privileged user and I also have sole access to the root account. Because I am the only administrator of this box, I frequently su over to root for administrative tasks. The problem is that many of the user configuration I've become accustomed to are only configured on my day-to-day account (.vimrc, .bashrc, .screenrc, etc). Other than giving my day-to-day user account privileges to perform administration tasks, how would I go about sharing configuration between these two accounts?
Possible Duplicate: Can history files be unified in bash? I have bash running in an ssh session, call this session A. I leave the office, go home, ssh to the same box, call this session B. From session B, I'd like to be able to look at the history of session A.
How can I get/filter history entries in a specific range?I have a large history file and frequently usehistory | grep somecommandNow, my memory is pretty bad and I also want to see what else I did around the time I entered the command.For now I do this:get match, say 4992 somecommand, then I do history | grep 49[0-9][0-9]this is usually good enough, but I would much rather do it more precisely, that is see commands from 4972 to 5012, that is 20 commands before and 20 after. I am wondering if there is an easier way? I suspect, a custom script is in order, but perhaps someone else has done something similar before.
Currently the terminal prompt looks like this:[karlis@karlis-desktop current_folder]$How can I minimize the prompt, so that it only shows $ or # without extra info in square brackets?I checked the preferences for the default Gnome-Terminal and Terminator - there are no settings for this. It is pretty hard to use terminal when working in directories with long names.
I've written a bash shell script (code provided below) that gives the user 4 options. However I'm having a little trouble with the code. Right now when they select option 3, to show the date.It loops over and over again.I have to close the terminal window to stop it because it's an infinite loop. How would I prevent this? Also quit doesn't seem to be working either.
#!/bin/bashe echo -n "Name please? " read name echo "Menu for $name[code]............
In linux how do I to get the ascii decimal/hex/oct code from a char or a ascii char from a decimal/hex/oct code. I see from the gnu sed user manual that I can use the d# o# x# to specify a character but I am not sure how to use that. If some one has a better way to get the the ` and ' chars through I want to sed with the backtick '`' character and ''' single quote character.
I am working on a simple script that should take two command line arguments, a [number] and a [name]. The first thing the script should do is check to make sure that no more and no less than two command line arguments have been entered when calling the script - an error message should be delivered if the condition is not true.
If two args have been entered, then the message 'processing "scriptname"' should appear, where scriptname is the name of the script being called. The script should then write to the screen "Hi [name]!", and should write this phrase [number] of times. For example, the command $ myscript 2 joe would produce the output: I have read the manual many times looking for examples, and I am very close by virtue of my own efforts. Further, I have searched these forums and others for good examples, which have also gotten me very close. Still my script is not completing the objective, and I am wondering if someone could point me in the right direction. Script:
i have a script where i need to pass an argument "1234:-)"if i run this as ./shell.sh 1234:-)it wont work because invalid character. i need to handle this with expect utility so if i pass it as ./shell.sh "1234:-)"no issue in bash but expect does not recognize this.