Programming :: Generating Files With Different Names At Each Loop In Fortran?

Nov 7, 2010

I am trying to write a loop to open four main-data-files. At each open of the main-data-file, I want the loop to open another four sub-files and split the data from the mail-data-file according to the creteria and dump into the four files. When the loop goes to the second main-data-file, it shall generate another 4 sub-files with different file name. And the process goes on. That means I will have total of 16 sub files for the four main-data-files. Each four files from the 16 files shall have specific name on it. Based on the code which I given below, I would say when the file at UNIT=100 is opened, 4 new files needed to be opened as well. They are:

maximum_dist_001_064.dat
maximum_dist_065_128.dat
maximum_dist_129_192.dat
maximum_dist_193_256.dat

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Programming :: Fortran How To Open A File In Loop

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#!/bin/basth
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do
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[code]....

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Code:

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So I had to use

Code:

for i in 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

Secondly, it was simply

Code:

#!/bin/bash
for i in 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
do

[code]....

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Apr 1, 2011

*I'm using Ubuntu 10.10

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I would like to "ls" to each file found with its complete path and with its basename too.

Code:
files=$(find . -type f)
for each in "$files"
do
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[Code].....

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[code]....

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[Code]...

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Code:

#include <stdio.h>
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[code]....

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Code:

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[code]....

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Code:

for line in $(cat tmpSearch)
do
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Code: !add2.f90
Module add2
Implicit none
Contains

[code]....

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