I want to count the number of files in each sub folder of a directory structure. At the moment I can do:
ls -1R /Folder | wc -l
Which lists the item count for all the folders as one. I can do:
ls -1R /Folder wc l
Which lists all the folders in the top level and all the items. Is there any way to get the list of folders and then item count for each folder?
I need to count files in a dir which were updated yesterday.
ls -lth | grep -i 'Jul 7' | wc -l
The dir holds files of last 15 days and total count is as 2067476. Is it efficient to count the files using perl? I have developed the following perl script making use of system().
Code:
#!/usr/bin/perl
@months = (Jan,Feb,Mar,Apr,May,Jun,Jul,Aug,Sep,Oct,Nov,Dec);
($sec,$min,$hour,$monthday,$mon,$year,$wday,$yday,$isdst) = localtime(time);
[code]....
I have log files that should be parsed and then deleted by a script on a regular basis. Sometimes things don't work for a variety of reasons and the log files sit and sit and are never dealt with. What I need is a small script that can give me the files older than X days and a count of those files.
What I have so far helps me take care of things manually but I need a little automation in my life Here is what I have: I can count all the files in the necessary directories recursively with this: ls -laR | wc -l And I can find all the files that are older than 10 days that haven't been deleted yet by doing this: find /home/mike/logs -type f -mtime +10 But how do I put both of them into a script that will just give me the end number of both?
Word Count for all files in a directory
View 1 Replies View RelatedI have the following perl/DBI script:
Quote:
#!/usr/bin/perl
use DBI;
my ($db, $user, $pw) = ('dbname', '****', '***********');
my $dbh = DBI->connect("DBI:mysql:$db",$user,$pw) or die "Cannot connect to $db: $DBI::errstr
[code].....
The error message is
[Wed Feb 24 13:03:27 2010] myscript.cgi: DBD::mysql::st execute failed: Column count doesn't match value count at row 1 at myscript.cgi. [Wed Feb 24 13:03:27 2010] myscript.cgi: DBI::db=HASH(0x8a30c60)->errstr
I'm working on a bash script that will go through a directory, find the sub-directories that have been created since the last time the script ran, count the results, and output that integer (will most likely be '1' or less per each instance run) to a file. Give the circumstances, my previous (and very limited) experience with bash is not sufficient for me to pull this off. since it probably has bearing, is that my mail server stores files that it flags as viruses in a folder. It creates a sub-directory for each virus that it quarantines .I want to count those subdirectories and graph them with MRTG. Hence the script. I'm going to post what I've got so far and the purpose of it, because I'm told I have a very odd and efficient way of doing scripting.
[Code]...
But then it dawned on me that it wouldn't work because I would have to not count the directories that have already been counted and count the ones that have not been counted. Given that the purpose of this is to generate a graph about every 5 minutes, using find won't work because, to my knowledge, that will only find things based on whole day values, I need it almost down to the minute.
I am new to perl scripting and wrote a perl script to read the directories and files and count the no of files in each directory and generate a log file. The problem is it is not printing anything to the log file. I am copying the script below.
!/usr/local/bin/perl
$dir= 'c:My ProjectsPerl ScriptsNew Folder' ;
$directory_count = 0;
$file_count=0;
[code].....
what I got - from a crontab run a script (understand that part), this script needs to count the amount of files in /outgoing/, then take 30 less that number, and move that many files from /readycalls/. I need to keep the asterisk outgoing que full of .call files with out having to many in there at any given time.
View 3 Replies View RelatedI have a lot of pdf files and I want to convert them to a lower quality for the web. I tried to use the following command (using ghostscript): Code: gs -sDEVICE=pdfwrite -dCompatibilityLevel=1.4 -dPDFSETTINGS=/default -dNOPAUSE -dQUIET -dBATCH -sOutputFile=output.pdf input.pdf Is there a way to make a batch to do this for all pdf-s in a folder?
View 4 Replies View Relatedhow I can monitor a folder and get the name of newly created files or files that their size is changing? (in Perl or Linux shell script)
View 5 Replies View RelatedI want to delete all files within a specific folder without actually deleting the folder, what is a good bash command for this?. I found this one but encountered some errors even though I am executing it within the specific folder:
useratdebian:/home/user/folder# find . -type f -exec rm -rf {} ;
[1] 5052
useratdebian:/home/user/folder# find: missing argument to `-exec'
[1]+ Exit 1 find . -type f -exec rm -rf
The command as it appears is:
find . -type f -exec rm -rf {} ;
how to delete only the files contained within the folder called "folder" for example?
I have a script that checks a folder for zip files than moves them to a different folder. I want to check every 5 maybe 10 seconds and since cron is setup to run at least a 1 minute increment I'm not sure how to do that time check as probably a loop within the script. One other thing is once the time check is in the script how would a cron job be setup to run this script? Once the script is running cron doesn't need to run it again, is there a feature to check if it's running and if it's not then run it?
find /export/xxxshare -name "*.zip" -exec mv {} /export/store ;
Can someone please help me on how can i create a script that will monitor file creation on a single folder and sending the newly created file on a separate folder? Only the new created file must be transffered or copied to the other folder. The old ones remains.I urgently need this for production deployment.
View 8 Replies View RelatedWay to test permissions on all files/folders into a folder recursive, then if those are not user:user then do :
Code:
chown user:user thatconcernedfile
The problem with that
Code:
chown user:user -R /folder
is that it is doing changes on file permissions whihch are already ok. If you wanna maintain a specific permission on a folder this is really not good this :
Code:
while [ 1 ] ; do
chown user:user -R /folder
# /folder contains 6.0 Tb
sleep 2s
done
I have these but not working.
size_t count_words(const std::string& s)
{
std::istringstream is(s);
return distance( std::istream_iterator<std::string>(is),
std::istream_iterator<std::string>());
}
and
std::string s; // word count
unsigned int wordno = 0;
while(getline(myfile, s))
{ ++wordno;
if(s.empty())++ wordno;
else wordno += count_words(s);
std::cout << s << '
';
}
myoutput1<< "Number of words : " << wordno << '
';
myoutput1 << "
Word" <<" " <<" Occurrence" <<endl;
myoutput2<< "Number of words : " << wordno << '
';
myoutput2 << "
Word" <<" " <<" Occurrence" <<endl;
I have a really deep directory tree on my Linux box. I would like to count all of the files in that path, including all of the subdirectories.
For instance, given this directory tree:
/home/blue
/home/red
/home/dir/green
/home/dir/yellow
/home/otherDir/
If I pass in /home, I would like for it to return 4 files. Or, bonus points if it returns 4 files, 2 directories. Basically, I want the equivalent of right-clicking a folder on Windows and selecting properties and seeing how many files/folders are contained in that folder.
How can I most easily do this? I have a solution involving a Python script I wrote, but why isn't this as easy as running ls | wc or similar?
I would like to count all the jpgs in my home folder I need a command like this:
~$ Sudo count -R /*/*.jpg
I have written a code on Linux that searches a long dictionary. I have used hsearch() function but the problem is it does not work. This is my code://Search the count values from the dictionary.
Code:
#define _GNU_SOURCE
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<search.h>
#include<inttypes.h>
#include<math.h>
[Code]...
I open each DIC file, get the word from it and search the hash table and extract the key from it. The problem with the above code is that it is able to make the hash table but it returns NULL when searching. It should not return NULL in any case because all words from DIC files are there in the dictionary. I am not able to figure out why?
I have a file with lines that look like this:
Dev/7_Texas2004/4_Caves/page.htm
Dev/7_Texas2004/5_SanMarcos/page.htm
Dev/7_Texas2004/6_Austin/page.htm
And I'm trying to count the number of slashes in each line. I figured (with my limited knowledge of bash) that the best thing to use would be sed. So I ran this to print "not /": sed '!s////g' file # and eventually adding " | wc -m" to it. and I got the same result as if I ran cat, no modification at all:
[Code]...
I want to count the lines of all files in this directory and all its subdirectories, but exclude directories "public", "modules", and "templates".
View 2 Replies View RelatedI need to search through HTML files to count the number of <li> tags nested within the first <ul> tag:
Code:
<ul>
<li>text 1</li>
<li>text 2</li>
</ul>
...
<ul>
[Code]...
Unfortunately, the second grep is greedy swallowing everything up to the last </ul> close tag. (The desired result is 2.) Speed is an issue as I will be searching through 350,000 files.
How do I count the number of occurrence characters in a string in an efficeint way ?
How do I reverse the words in a string with out using temp variables if possible . (if not possible use temp variables ?
Why do I specify dependedcies for header files in the Makefile ?
I am using RHEL 4.5.
I am trying to count no. of characters in a word but it is coming one more than what it actually should be.
Code:
I can have a work around by subtracting 1 from the output (6-1=5 in this case). BUT, I am just curious to know, why the character count is coming as 6 and not 5.
im stuck with something trivial again. so i want to calculate how much time my programm runs:
int main (int argc, char* argv[])
{
clock_t end, start;
start= clock();
int i;
int p, q, r;
FILE* f_out_loc;
[Code]....
it returns 1.12 sec. looks like clock() doesnt count how much system() works .... is it possible? and how do i calculate the whole thing?
Exist it a perl function to count how much each array element is into array?
View 14 Replies View RelatedWhat I want to do is from a file having block like
<event>
8 3 0.2685416E-02
2 -1 0
21 -1 0
[code]...
The first line after the "<event>" is its process-id, so I would like to have at the end a summary of how many "event" block I have for each type, ie how many
6 1 0.2685416E-02
or how many
7 2 0.2685416E-02
etc etc
I do not know in advance how many different-kind of block I will have, so it has to be a bit smart to scan the file, and make an new "summary" info for each unique type I was using something like
awk '/<event>/,/</event>/{if ($3 -eq 0.2685416E-02 ) { print $1" "$2" "$3}}' file > out
and then
grep -c "$1" "$2" "$3" but with no success since my awk commands prints all lines of each block
Suppose, that in advance I do know the $3, ie the 0.2685416E-02 which is a kind of weight
I need something to make a script that will search some logs and extract IP hits from one country only. Let's say UK. I guess I need to use GeoIP or some database. I just need a very simple bash, perl, php script that will do this job. Just search threw logs (apache) and then give me number of hits found from UK.
View 5 Replies View RelatedI love medit for text editing, but it's missing a word count feature.
I found a "Statistics for medit" script on the Arch Linux Forums, but after installing as instructed, there was no popup.
So I set it to output to a pane instead, and I got:
Code:
My scripting skill is extremely basic, so any troubleshooting. (I'm using CrunchBang Statler, which is Debian Squeeze based.
This has to also show the line count. I can get it to show the files but not the line count. What is the single command used to identify only the matching count of all lines within files under the /etc directory that contain the word „HOST? List only the files with matches and suppress any error messages.
View 4 Replies View RelatedI'm running a find. -name pattern to find some files, and I'd like to elegantly get the total number of lines in these files. How can I achieve that?
View 4 Replies View Related