I'm having a bit of trouble getting the OR operator to work.This is the code that I have:
global.php:
Code:
$vars["admin link"] = "<a href='/path/to/admin.php'>Admin</a>";
$vars["admin ip"] = "xxx.xxx.xxx.xx1";
$vars["admin ip2"] = "xxx.xxx.xxx.xx2";
[Code]...
I'm very new at Bash scripting and have a bone head issue that I'm trying (and failing) to resolve. I cannot get this one IF statement to work, it seems the comparison operator does not think the resulting number from the $b*$c+$b operation is an integer even though it is a number. Below is a small proof of concept script with the bit I'm having trouble with.
Code:
#! /bin/bash
a=800
b=700
c=.15
if [ "$a" -le "$(echo "($b*$c+$b)"|bc)" ]
[Code]...
I'm having a bit of an issue using overloaded operators in an already overloaded operator. In my following code, I have overloaded the && operator to compare two Course objects. The operator in turn goes to a function which calls other overloaded operators to compare private object variables of that object to compare them.
View 8 Replies View RelatedI have a binary value which I receive from a controller. Say this binary value is 42. Just plain hex 42. If you would look at that byte in a debugger you would see 42.Now this value hold 8 bits each indicating a high or a low output. So 0x42 = 01000010b. Which means bits 1 and 6 are '1'.When I would want to find out which bits are set and which are not in a language like C, I simply do:
Code:
mask = 0x80;
if (binval & mask) {...}
etc..
However I am programming in TCL, and I try to do:
Code:
set mask 0x80
if { [expr ($binval & $mask) > 0] } {...}
etc...
this fails. At the moment the expr is executed, $binval is evaluated and substituted so the expression I am evaluating is
Code:
set mask 0x80
if { [expr ('B' & '0x80') > 0] } {...}
etc...
Eventually I got it working by converting the $binval into a '0x42' string value, like this:
Code:
binary scan $binval c byte
set byte [format "0x%0x" $byte]
set mask 0x80
if { [expr ($byte & $mask) > 0] } {...}
etc...[
Then the expression yields what I want. But this seems so stupid and clumsy. Isn't there a better way where I can compare two binary values without conversions?
I have a simple program from book C++ cookbook, page 291, 8.3, Using Constructors and Destructors to manage resources (or RAII), but it can not get compiled in my g++
------------------------------------------------------------------------------------------------
// Example 8-3. Using constructors and destructors
#include <iostream>
#include <string>
using namespace std;
[code]....
Is there a way to achieve the following with the square bracket operator?I have a class:
Code: Select allclass A
{
public:
void SetValue(int index, Item* B);
private:
int m_iCount;
ItemCollection Item_Collection;
[code]....
The probelm is that I am not just blindly assigning whatever given on the right hand side to the returned value from operator [], I need to verify it's not NULL, and it is not already there in the Item_Collection, and I also need to increase the count.
I know it is wrong to use the "==" operator to compare the equality of two floating point numbers. Logically it would seem that if the "==" operator is not usable for floating point comparison, then the "<=" operator would also not be usable. Is this true? The lack of google search results on this topic made me think that it must be true. If that is true, then is it true that the only way to compare floats with <= or >= is with something like the code below? Code: bool smaller_than_or_equal(float a, float b) {
if ( fabs(a-b) < EPSILON){return true;}
else if (a < b) {return true;}
else {return false;}
} I think this is a general question, but if specifics are necessary, I am using the C++ language to code at the moment.
I am trying to learn C++.I implemented a simple archive program, and I am in a situation in which the user is prompted by a menu to make a choice.So I have some cout instruction to illustrate the possible choices and then
int choice;
cin>>choice;
and everything works fine.I introduced this code in a "while" loop that checks wether the choice made by the user is valid or not:
bool check=true;
int choice;
while(check)
{
cin>>choice;
if(the choice is valid) {...;check=false}
else cout<<"please make an other choice"
}
What is happening is that if by mistake the user introduces a character in place of a number, the loop repeats indefinitely because the program, when it get to the "cin" instruction, does not pauses to wait for a new input.
Can one of you point me towards a comprehensive print function tutorial in perl? I was under the impression that everything within quotes will get interpolated - but I am running into exceptions where it is not desirable to run some varaibles under quotes.
ordinal.pl
1 #!/usr/bin/perl
2 $idx = 1;
3 foreach $letter (a..z) {
4 print "Letter #",$idx++," is: $letter
";
5 #print "Letter # $idx++ is: $letter
[Code]...
I've been reading and googling, etc. I've seen some things, but not a definite explanation of this. What is the appropriate way to mimic a C ternary operator using Python? Isn't there an exact proper way to do it? Any difference for using lambda functions? I'm sorry, but I've been searching and it's ambiguous to me how this should be handled. I would appreciate a person's help on this. I came up with this link, but I'm wondering if I'm missing something.[URL]...
So, is that it? In Dive Into Python, it's using the and-or trick. Well, if the above post is the full explanation,
how to overload the subscript operator ([]) for a list class?
Code:
template <typename T>
class list
{
public:
struct node
[Code]...
I have tryed out this operator on program:
Code:
#include <iostream.h>
#include <iomanip.h>
#include <fstream.h>
ofstream myfile;
[code]...
which definitly is not the same number. I guess somewhere in the convertion from double to char* ("<<") something is not right and what can i do to save these double numbers in an accurate manner in a file?
I would like to compare the nmlookup result of IP's stored in the file ips with a list of PC names stored in the file pcs.
Code:
for line in `cat "ips"`
do
[code]....
does the assignment operator copy all the members also for structures containing STL objects strings,vectors,vectors of vectors...)? I did try it on my platform,and it works that way (copying all the fields),but i was wondering if it is a standard behavior or not.
View 2 Replies View RelatedThis one is driving me crazy.
My .bashrc is set as:
if [ -d ~/.bashrc.d ]; then
for file in $(/bin/ls ~/.bashrc.d/); do
[code]....
My compiler won't find <new>. Since it's such a basic function, I'm a bit confused. Is <new> supposed to be in a file of its own? Where do I find it? And if it turns out to be missing on my computer, where can I find a <new> one? Or do you see anything else that I do wrong?
After some trying out, it seems I can't find stuff like iostream or any other basic stuff either. The compiler is prolly looking for them at the wrong place. Does anyone know how I change or add paths for the compiler to look in when using the "<>" operator?
if anyone knows plz explain this conditional operator timeout ? : MAX SCHEDULE_TIMEOUT
View 2 Replies View Relatedi am not able to understand the appropriate thing to put in the google search...
Is there a way to use the ?: operator for if-else decision in a shell script?
edit: the 'question mark - colon' operator (just editing so that its searchable by someone in need :-P)
$dec93 = 93;
$ser = SERVO;
$lbit = uc(sprintf("%02x
", $dec93));
if($lbit == 5D){
print DATA "Byte11: $fbits11=$bstr11 Bits:[95-88] $ser
";
}else{
sleep(1);
}
Why do I get this error? Bareword found where operator expected at C:Perl ScriptsLbits.pl line 64, near "5D" (Missing operator before D?)
Does anybody here use Tyan System Operator (TSO) in ubuntu sever? It seems that the packages are for redhat only
View 3 Replies View RelatedI have been spending several days getting wxwidgets to work in code::blocks ide on several different platforms. Now I am down to one instance that I can't figure out. I have wxwidgets working in Fedora 13 x64, but cannot get it to work in a Fedora 13 x32 version. Actually, wxwidgets seem to be installed OK, but I run into compiler errors when I try to compile the default wxhello project. I get quite a few messages, in different header files, of this type:
/usr/include/assert.h:39:42: error: missing binary operator before token "("#if defined __cplusplus && __GNUC_PREREQ (2,95) From my friend Google this would seem to be caused by an older version of boost (before 1.37) - see http://bugs.xmms2.xmms.se/view.php?id=2215 ("It is an issue with old versions of boost and gcc4.4 http://gcc.gnu.org/bugzilla/show_bug.cgi?id=36453 It is fixed in boost 1.37")
I did a yum info command on both systems for every relevant package I could think of, including gcc(v4.4.4), gcc-c++(4.4.4), libgcc(4.4.4), libstdc++(4.4.4), boost(1.41.0), wxGTK(2.8.11), wxBase(2.8.11). Both systems are fully updated and have the same versions, with the only difference being 32 vs 64 bit. The same headers compile with no errors on the x64 system, but not x32. I have been able to find no other reason for this error than older versions of the preprocessor, yet that is apparently not the case here).
I'm trying to make a bash script that takes away two decimal numbers. This is to work out partitioning information.
Code:
hddsize=`sudo parted -s /dev/sda unit GB print | grep "Disk" | tr -d [A-Z][a-z] | tr -d '/: '`
trimsize="1.5"
partitionendsize=$(($hddsize - $trimsize))
I get an invalid arithmetic operator. Not sure how to minus these two numbers. Is it a floating point issue?
I am using "if" to force a word under the condition that the first letter of that word must be a letter of the alphabet, regardless of capitalization, using the " "" != "" " syntax.
Like so:
Code:
if [[ "$interface" != "WHAT DO I PUT HERE?" ]] ; then
echo "Invalid input"
exit 1
fi
if [ $games -gt 0 ] ; then
echo ""
echo "*** New Game! ***"
[code]....
i write this script:
[Code].....
i make this script to become a service ( i test it from bash, and my script work good), my problem is when i telnet to my local host (127.0.0.1) via a personal port like 5555 telnet give this error: ")syntax error: invalid arithmetic operator (error token is ", i know this error is for echo $(($A+$B)) and i know that telnet can not calculate $A+$B and the error is for this
This code will execute fairly well, however, if you enter multiple values that are not A/a or b, 1 or 2, then when the program resets, cin does not behave normally. Instead of waiting for input, it acts as if it has already been given input, and the input is the next character from the one entered.For example, entering "345" and submitting it at the (cin >> a line will individually pass the values 3, 4, and 5 through the if/else and switch statements, rather than only inputting the first value, 3, or all the values, 345.
If you enter, for example, "3343634563456345", then it will pass through the do{}while(); loop 16 times, with each pass having a = to the next character value. The cin >> a; is performed, and this is verifiable in GDB, however it never asks for input from stdin, and instead gets its input from somewhere else. How can I observe that, and what is going on?Furthermore, if you enter "cdefghijklmnopqrstuvwxyzab", it will pass through 25 times, and stop at a, which goes through the switch, and ends at a case statement that does not adjust the false value of mreset, thereby allowing the program to end.
I got a problem about assert() on linux/unix && gcc , I wanna know how does assert() work,I mean that how does the assert() make the programme exit? Is assert() send SIGSEGV to programme or called function exit() or other ways?
View 4 Replies View RelatedI've tried instralling the c and c++ compilers on my fedora 13 machine and none of them seem to work. For example. i have this extremely simple c program that i try to compile and nothing works.
Code:
#include "stdio.h"
printf("Hello World"); when i type Code: [####localhost Desktop]# cc hello.c i get this error Code: hello.c:3: error: expected declaration specifiers or �...� before string constant
hello.c:3: warning: data definition has no type or storage class
[code]...
i've tried intalling a group of developers tools using yum groupinstall "Developers Tools" and nothing......
I have a script that will build a list of hosts and it works fine Code: for ((i=$START; i<=$END; i++)); do echo "$NAME$i"; done But I need it to build the START and END on different number formats (i.e. 1 -> 10, 01->10, 001 ->010)
I am trying to use the seq command but can't get it to work quite right with the -w flag in the following Code: for ((myseq=$START; myseq<=$END; myseq ++)) do echo "$NAME${myseq}" done I am fully aware that this syntax is probably wrong, and need to know how to correct it.
I've tried instralling the c and c++ compilers on my fedora 13 machine and none of them seem to work. For example. i have this extremely simple c program that i try to compile and nothing works.
Code:
#include "stdio.h"
printf("Hello World");
[Code]....