What I would like to do is to print the contents of all text files in a particular directory, recursively. Problem being that there are directories and possibly binaries scattered around in the filesystem as well.
Trying cat * works as long as there are no directories in there, but when there are it gives an error instead and prints nothing.
I'm sure it's easy using file -f or something but I can't figure it!
I want to list recursively all files in given direcotry, with their fullpath and their timestamps.Something like this:10:30 Dec 10 2010 /tmp/mydir/myfileI've tryied with:find . -type f -exec ls -la {} ;but that don't give me the fullpath.
View 3 Replies View RelatedIs there any Linux application for finding the folders with the most number of files? baobab sorts folders by their total size, I'm looking for a tool that lists folders by the total number of files in it.
The reason I'm looking is because copying tens of thousands of small files is excruciatingly slow (much slower than copying a few large files of the same size), so I want to archive or delete those folders with high file counts that that will be slowing down the copying (it won't speed things up now, but it would be faster when I need to move/copy it again in the future).
I am attempting to use the zip command with the '-x' option to exclude a folder e.g. 'zip upload.zip public_html -x public_html/jquery/*'. However, parts of this folder are still being added to the archive. I made a shell script (saved as 'compress.sh' and ran as '. compress.sh') to do the archiving so I could test adding nested wildards for multiple subfolder levels.
Code:
#!/bin/bash
rm -f upload.zip
zip -r upload.zip public_html
-x public_html/jquery
[code]....
Each new line I added here that has the nested wildcards made the archive file size a bit smaller. Adding more /*'s than this didn't affect the file size. Even after all this though, there were still a couple megabytes of files and folders from the 'jquery' directory that were added to the archive.
Here's some examples of files and folders that were created after I unzipped the archive:
public_html/jquery/js/tablesorter/addons/pager/icons [folder]
public_html/jquery/js/tablesorter/addons/pager/.svn/entries [file]
public_html/jquery/js/tablesorter/build/.svn/text-base/js.jar.svn-base [file]
Why is it that despite all the -x lines, the files and folders like these were still being added to the archive? How can I simply recursively exclude the entire public_html/jquery folder from the archive?
I have a directory: /var/www/html/something/
and it's got tons of files and directories, some containing hidden files.
I want to move all the contents of something including hidden files up to the site root at: /var/www/html/
What is the proper command for this?
1 List the contents of directory, /dev using a detail listing format and page by page.
2Mount the CDROM to the directory, /media/cdrom.
3 Delete the file "/home/student/myfile" without any confirmation (Assume you have the required file permission to delete this file).
I can't seem to find any info on a terminal command that lists the contents of a directory with page breaks so that I can view the contents of a very large folder (such as /usr/bin) because if I use ls, it prints so many names that scrolling up won't even cover all of them. We all know the obvious solution is to use a graphical file browser, but I tend to shy away from depending on graphical utilities simply because command line feels faster.
View 3 Replies View RelatedWhen I run "ls -al somedir*" (I use the "ll" shortcut, actually), Linux not only list files that match, but also the contents of directories whose name also happens to match.Is there a way to limit "ls" so that it will only show names (files and directories) and ignore the contents of the directories?
View 2 Replies View RelatedUbuntu 10.04
I want to copy all directories, files, and hidden files and hidden directories with one command. I want these items to replace any same items in the target directory.
I have tried several things, such as:
cp -r *
cp -aR *
but I only seem to get visible files and directories. Obviously, I am missing something. (A brain, probably....)
ls -al ../public-back
drwxrwxr-x 4 apache apache 4096 Apr 19 03:32 templates
ls -al ../public-back/templates
drwxrwxr-x 2 apache apache 4096 Apr 19 03:33 content
[code]....
How do I move the contents of /public-back/templates recursively with permissions into /public/templates ?
I have a really deep directory tree on my Linux box. I would like to count all of the files in that path, including all of the subdirectories.
For instance, given this directory tree:
/home/blue
/home/red
/home/dir/green
/home/dir/yellow
/home/otherDir/
If I pass in /home, I would like for it to return 4 files. Or, bonus points if it returns 4 files, 2 directories. Basically, I want the equivalent of right-clicking a folder on Windows and selecting properties and seeing how many files/folders are contained in that folder.
How can I most easily do this? I have a solution involving a Python script I wrote, but why isn't this as easy as running ls | wc or similar?
The rm command man pages discusses removing files or directories recursively. So what is meant by deleting a file or directory recursively? And what are some reasons for doing so?
View 3 Replies View RelatedI'm planning to writing a script to rename files recursively.
To be said that I'm using /bin/sh (not /bin/bash) as this is the only shell available on the busybox of the linux router (tomato) I'm using.
Basically I would like to rename files with extension .jpg using as a suffix the filename of another file in the very same directory with extension .avi
The reason for this is because pretty much all the DLNA devices like modern TV playing .avi files will display a thumbnail of the video when browsing the filesystem, however to do so they'll need .jpg image wit hthe same filename of the video in the very same directory.
I made an account under freeshell.org and it has been very satisfactory so far. I recommend everyone getting an account under freeshell.org. But anyways, how do I find files over, for example, 500 KB, in the entire, my shell account?
View 1 Replies View RelatedI'm a frequent user of grep. I know that I can recursively search a directory using the -r flag:
Code:
// will recursively search all files
grep -r 'some string' *
However, if I want to limit my search to PHP files, the -r flag is suddenly useless:
Code:
// for some reason, this only searches the PHP files in the current dir
grep -r 'some string' *.php
Any good way to recursively search a directory and its subdirs for a string but ONLY look at PHP or HTML files (and possibly TXT files too) ? I'm really hoping for a nice, short command that doesn't involve using an exclude file and which isn't really painful to type. I do this kind of search very frequently and have resorted to either searching EVERY file which is really slow (TAR and ZIP files really slow it down) OR typing repeated commands to search *.php, */*.php, etc.
I'm using a mac, and just transferred a bunch o photos from another computer, and as it turns out, there is a bunch of duplicates.I'm not too familiar with the mac terminal, but if there is a solution for linux, it will probably work for the mac.Just need to be able to recursively scan all folders in my Pictures folder and then Delete them.
View 1 Replies View RelatedAt the linux command line, I'd like to compress all .pdf files in a directory, any of it's subdirectories and so on - but only .pdf files. I'm struggling to figure out the syntax
View 2 Replies View RelatedI'm under linux . by default, other user can't read anything under my home directory. let's see my home directory is /home/superman , and I tried to use
chmod +r /home/superman
to let others can acess files under my home directory , but it does not work .
I need a either a script or perl script that will allow me to mass rename files, folders, and sub folders. I need to replace special chars in the current file names with underscores. I was able to make this happen in a single directory, but not recursively.
Here is what does it in a single directory.
for file in *
do
mv "$file" $(echo "$file" | sed 's/[^A-Za-z0-9_.]/_/g')
done
I am new to linux as well as awk, grep or sed. I need a find and replace command single liner or script that loops trough input file (file1) and find the particular input in file2 and add "!" in front of the found string.
Example:
input file: file1
g+h=o+p
a+b=c+d
file2 (file that need to look for)
a+b=c+d1e105
x+y=z+s5e105
g+h=o+pabcdefg
t+r=w+qxvyderf
Output file (file3 should look like this)
!a+b=c+d1e105
x+y=z+s5e105
!g+h=o+pabcdefg
t+r=w+qxvyderf
I have tried many awk and sed method of find and replce but it did not work the way I wanted. This is mainly due to my lack of experience in awk and sed. The program should loop trough file1 and find in file2 and output in file3 for the 1st (g+h=o+p) set then repeat the same process again for set 2 (a+b=c+d).
I'm able to use the following to remove the target directory and recursively all of its subdirectories and contents. find '/target/directory/' -type d -name '*' -print0 | xargs -0 rm -rf
However, I do not want the target directory to be removed. How can I remove just the files in the target, the subdirectories, and their contents?
I would like to overwrite files in a directory tree, recursively. The ones I would like to overwrite match the filename "x_alpha*.png" and have a size exactly 456 bytes. Is there any way to search for these recursively in a directory tree, and overwrite them with a reference file, for example "e:mydirgood.png"
I am using Windows 7, but I have UnxUtils, so I can use those too. What I am looking for is something like this, generated automatically:
copy /y e:mydirgood.png e:mydiracx_alpha0023.png
copy /y e:mydirgood.png e:mydirefgx_alpha0045.png
copy /y e:mydirgood.png e:mydirhx_alpha0248.png
i would like to find and backup all *.mp4 files from /Pictures and its sub-directories and move them to a single directory on a remote. I can find and move the files but I don't want the directory structure...just the files to be placed in the remote directory.
To find my files I use
rsync -r -a -v -e "ssh -l user" --delete --include '*/' --include '*.mp4' --exclude '*' /home/drew/Pictures/ remoteserver:/Users/drew/mp4
but this creates all the subdirectories
I also tried
find ~/Pictures -name "*.mp4" -exec rsync -r -a -v -e "ssh -l user" --delete {} remote:/Users/drew/mp4 ;
This works but takes forever
I need to strip the executable flag from all files within a certain directory and sub directories. Right now I'm doing it with a 2 step process
find /dir/ -type f -exec chmod ugo-x {} ;
find /dir/ -type d -exec chmod ugo+rx {} ;
Is it possible to modify the first line so that I can strip exec flag from all non-directory files? Since this needs to be done on a fairly regular basis across a lot of directories and files, I'd prefer not to use a bash script which would slow it down.
suppose in my current directory, I have 50 sub-directories. Now, I am interested only in about 20 of those sub-directories (whose names match a pattern). I would like to recursively list the contents of these 20 sub-directories. How do I do that ? I would like to do this in Solaris 10 and Linux(RHEL 5.x).
View 3 Replies View Relatedlets say I have a project that have generated lots of xml files. Though all these xml files point to a location with the text name TEXT15. I want to change all the files that containts TEXT15 and change it to TEXT16. This actually works for files in a folder but not recursively in all the entire files....perl -pi -c 's/TEXT15/TEXT16/g' ./* but I have many subfolders and within this more subsub folders....i just want to do this recursively.
View 2 Replies View RelatedI'm trying to make a shell script that will list the 50 newest files in a directory with several subdirectories in. I've been trying with the find-command with no luck and now I've figured I should probably use ls. The problem is when I do "ls -lRt | head -50" it will do 1 directory at the time. It will not first make the full list and then sort it. This will display all items in first directory, sorted, then the newest directory will be sorted and displayed. So I figured I have to sort the whole process of ls before I limit the head. So this is where I am at now: ls -lRt | sort <something clever here> | head -50
Only doing a "|sort|" will sort it by name if I understand it right and I don't know how to solve it. Here's also my first attempt if that is of any interrest or help, this was limited by the change status time of files (so some lists got very large). These lists dit not get sorted by time and I could not find any way to do so.find $ftpDir -ctime $time -type f -print > $ftpFileLsAny help on this would be appreciated since I'm sort of stuck now. After reading manuals for all the options I can think of and still there's just a big blur in my head..
I have an archive directory that needs to be cleaned up once per quarter. The top level (/data/archive/*) directory names change daily, as well as the subdirectories and the filenames (the application names everything according to date). Also, there are two top level directories, bin and incoming, that we can't touch. I want to write a shell script that loops through the 15 or 20 top level directories and deletes all files and subdirectories older than 3 days (skipping the bin and incoming folders). Can someone get me started on a script? I am kinda new to shell scripting.
View 2 Replies View RelatedI have a bunch of files on a Ubuntu box, which have various characters in their filenames that Windows doesn't accept (mostly ":" and "*", but possibly others).What's the simplest way to get these all renamed and moved to a Windows machine? It's OK to replace these characters with something like "[colon]" and "[asterisk]".
View 1 Replies View RelatedAm using the below script to send mails as an sql output . but the below script sends the generated file even if it is empty (if there is no outputs generated from the sql command) .
I want to send mail only if the file has some valid outputs. How to do this
{code}
export ORACLE_BASE=/u01/app/oracle
export ORACLE_HOME=/u01/app/oracle/product/11.2.0/dbhome_1
[code]....